Find Leap Year in C++

Structure of the Problem Requirements 

In this problem we will learn how to find leap year in C++ program . In Gregorian calendar there are three requirements for leap year .

1. The Year is Divisible by 4.

2. The Year is Divisible by 100.

3. The Year is Divisible by 400.

All these requirements must be fulfil to prove a year a Leap Year . Here is the source code of this problem which help you in better understanding.

Source Code   

#include<iostream>

using namespace std;

int main ()

{

int year;

cout<<" \t \t \t Find Leap Year \n \n ";

cout<<" Enter the Four Digit of Year : ";

cin>>year;

cout<<endl<<endl;

if ( year%4 == 0 || year%400 == 0 || year%100 == 0)

{

cout<<"\t \t  Yes! The Year "<<year <<" is a Leap Year "<<endl;

}

else

{

cout<<"\t \t No! The Year "<<year <<" is Not a Leap Year "<<endl;

}

}

Output of the Program

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Asad Niazi is Software Engineer , Programmer, Web Developers and a young mentor of Tech Solutions Desk and Blogging Solutions . Asad Love to writes about Technology, Programming, Blogging and make money online.